Solve the equation 8x2+22x+15=0.
Question
Solve the equation 8x2+22x+15=0.
Solution
Sure, let's solve the quadratic equation step by step.
The quadratic equation is in the form ax^2 + bx + c = 0. Here, a = 8, b = 22, and c = 15.
Step 1: Calculate the discriminant. The discriminant (D) of a quadratic equation is given by the formula D = b^2 - 4ac.
D = (22)^2 - 4815 D = 484 - 480 D = 4
Step 2: Find the roots of the equation. The roots of a quadratic equation are given by the formula x = [-b ± sqrt(D)] / 2a.
Root 1, x1 = [-22 + sqrt(4)] / 2*8 x1 = [-22 + 2] / 16 x1 = -20 / 16 x1 = -1.25
Root 2, x2 = [-22 - sqrt(4)] / 2*8 x2 = [-22 - 2] / 16 x2 = -24 / 16 x2 = -1.5
So, the solutions to the equation 8x^2 + 22x + 15 = 0 are x = -1.25 and x = -1.5.
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