Solve the equation 7x2+22x+3=0.
Question
Solve the equation 7x2+22x+3=0.
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Solution
This is a quadratic equation of the form ax^2 + bx + c = 0. We can solve it using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).
Here, a = 7, b = 22, and c = 3.
Step 1: Calculate the discriminant, which is b^2 - 4ac. Discriminant = (22)^2 - 473 = 484 - 84 = 400.
Step 2: Substitute a, b, and the discriminant into the quadratic formula to find the solutions.
x = [-22 ± sqrt(400)] / (2*7) x = [-22 ± 20] / 14
So, the solutions are x = -42/14 = -3 and x = -2/14 = -1/7.
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