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What are the values of x that satisfy the equation 3 – 27x2 = 0?

Question

What are the values of x that satisfy the equation 3 – 27x2 = 0?

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Solution

Step 1: Write down the equation: 3 – 27x^2 = 0

Step 2: Rearrange the equation to isolate the term with x^2. This gives us: -27x^2 = -3

Step 3: Divide both sides by -27 to solve for x^2. This gives us: x^2 = -3/-27 = 1/9

Step 4: Take the square root of both sides to solve for x. Remember that the square root of a number y is both positive and negative. This gives us: x = sqrt(1/9) = ±1/3

So, the values of x that satisfy the equation 3 – 27x^2 = 0 are x = 1/3 and x = -1/3.

This problem has been solved

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