Solve the equation 28+8x2−30x=0
Question
Solve the equation 28+8x2−30x=0
Solution
Sure, let's solve the equation step by step:
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First, let's rewrite the equation in standard form. The standard form of a quadratic equation is ax^2 + bx + c = 0. So, we have 8x^2 - 30x + 28 = 0.
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Now, we can solve the equation by using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a). In this equation, a = 8, b = -30, and c = 28.
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Let's calculate the value under the square root in the quadratic formula, which is b^2 - 4ac = (-30)^2 - 4828 = 900 - 896 = 4.
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Now, we can calculate the two possible values for x: x1 = [-(-30) + sqrt(4)] / (28) = (30 + 2) / 16 = 2 and x2 = [-(-30) - sqrt(4)] / (28) = (30 - 2) / 16 = 1.75.
So, the solutions to the equation 8x^2 - 30x + 28 = 0 are x = 2 and x = 1.75.
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