3) 27x ^ 3 - 9x ^ 2 - x + 3 = 0 if x = 1/3

3x^2-7x-6=0

What are the values of x that satisfy the equation 3 – 27x2 = 0?

Determine the zeros and y intercept for the rational function: R(x) = (x^3 - 27)/x^2?Question 37Answera.(3, 0); noneb.none; (3, 0)c.none; (0, 3)d.(-3, 0); none

3x−9−11x−2=3x−8x+13

Solve for x : x6 – 26x3 – 27 = 0Select an answerA– 1, 3B1, 3C1, – 3D– 1, – 3