Solve for x : x6 – 26x3 – 27 = 0Select an answerA– 1, 3B1, 3C1, – 3D– 1, – 3

This equation can be solved by treating it as a quadratic equation.

First, let's substitute y = x^3. The equation then becomes:

y^2 - 26y - 27 = 0

This is a quadratic equation in the form of ay^2 + by + c = 0, where a = 1, b = -26, and c = -27.

We can solve this equation using the quadratic formula y = [-b ± sqrt(b^2 - 4ac)] / 2a.

Substituting the values of a, b, and c into the formula, we get:

y = [26 ± sqrt((-26)^2 - 41(-27))] / 2*1 y = [26 ± sqrt(676 + 108)] / 2 y = [26 ± sqrt(784)] / 2 y = [26 ± 28] / 2 y = 27 or y = -1

Remembering that y = x^3, we can find the values of x by taking the cube root of y:

x = cube root of 27 = 3 x = cube root of -1 = -1

So, the solutions for x are 3 and -1. Therefore, the correct answer is A– 1, 3.