Solve the equation 2y2+15y+7=0.
Question
Solve the equation 2y2+15y+7=0.
Solution
This is a quadratic equation in the form of ax^2 + bx + c = 0. We can solve it using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / 2a.
Here, a = 2, b = 15, and c = 7.
Step 1: Calculate the discriminant, which is b^2 - 4ac. Discriminant = (15)^2 - 427 = 225 - 56 = 169.
Step 2: Substitute a, b, and the discriminant into the quadratic formula to find the solutions.
y = [-15 ± sqrt(169)] / 2*2 y = [-15 ± 13] / 4
So, the solutions are y = [-15 + 13] / 4 = -0.5 and y = [-15 - 13] / 4 = -7.
Therefore, the solutions to the equation 2y^2 + 15y + 7 = 0 are y = -0.5 and y = -7.
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