This is a quadratic equation in the form of ax^2 + bx + c = 0. We can solve it using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Here, a = 7, b = 12, and c = 5.

Step 1: Calculate the discriminant, which is b^2 - 4ac.
Discriminant = (12)^2 - 4*7*5 = 144 - 140 = 4.

Step 2: Substitute a, b, and the discriminant into the quadratic formula to find the solutions.

y = [-12 ± sqrt(4)] / 2*7
y = [-12 ± 2] / 14

So, the solutions are y = -14/14 = -1 and y = -10/14 = -5/7.

Question

This is a quadratic equation in the form of ax^2 + bx + c = 0. We can solve it using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Here, a = 7, b = 12, and c = 5.

Step 1: Calculate the discriminant, which is b^2 - 4ac.
Discriminant = (12)^2 - 4*7*5 = 144 - 140 = 4.

Step 2: Substitute a, b, and the discriminant into the quadratic formula to find the solutions.

y = [-12 ± sqrt(4)] / 2*7
y = [-12 ± 2] / 14

So, the solutions are y = -14/14 = -1 and y = -10/14 = -5/7.

Knowee AI · Accepted Answer

This is a quadratic equation in the form of ax^2 + bx + c = 0. We can solve it using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Here, a = 7, b = 12, and c = 5.

Step 1: Calculate the discriminant, which is b^2 - 4ac.
Discriminant = (12)^2 - 4*7*5 = 144 - 140 = 4.

Step 2: Substitute a, b, and the discriminant into the quadratic formula to find the solutions.

y = [-12 ± sqrt(4)] / 2*7
y = [-12 ± 2] / 14

So, the solutions are y = -14/14 = -1 and y = -10/14 = -5/7.

Solve the equation 7y2+12y+5=0.