Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively. Are in contact on a frictionless surface as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is
Question
Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively. Are in contact on a frictionless surface as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is
Solution
To solve this problem, we need to use Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration (F = ma).
Step 1: Calculate the total acceleration of the system. The total force acting on the system is 14 N and the total mass is 4 kg + 2 kg + 1 kg = 7 kg. So, the acceleration (a) of the system is F/m = 14 N / 7 kg = 2 m/s².
Step 2: Calculate the force between block A and B. The force between block A and B is the force required to move the combined mass of block B and C with the acceleration calculated in step 1. The combined mass of block B and C is 2 kg + 1 kg = 3 kg. So, the force (F) is m*a = 3 kg * 2 m/s² = 6 N.
Therefore, the contact force between block A and B is 6 N.
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