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Two blocks of masses m = 2 kg and M = 5 kg are in contact on a frictionless table. A horizontal force F = 35 N is applied to m. What is the force of contact between blocks ?A 25 N  B 40 N C 60 N D 10 N

Question

Two blocks of masses m = 2 kg and M = 5 kg are in contact on a frictionless table. A horizontal force F = 35 N is applied to m. What is the force of contact between blocks ?A 25 N  B 40 N C 60 N D 10 N

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Solution

To find the force of contact between the blocks, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Step 1: Determine the acceleration of the system. Since the table is frictionless, the only force acting on the system is the applied force F. We can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

For the block with mass m = 2 kg, the applied force F = 35 N. Therefore, the acceleration of the system can be calculated as follows: a = F/m = 35 N / 2 kg = 17.5 m/s^2

Step 2: Calculate the force of contact between the blocks. Since the blocks are in contact, they experience the same acceleration. According to Newton's third law, the force of contact between the blocks will be equal in magnitude and opposite in direction to the applied force on the smaller block.

Therefore, the force of contact between the blocks is equal to the force applied to the smaller block, which is 35 N.

So, the correct answer is A) 25 N.

This problem has been solved

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