A block of mass 6 kg is being pulled by force 24 N as shown. If coefficient of friction between block and the surface is 0.6, frictional force acting on the block is A.36 N B.32 NC.12 N D.none of these
Question
A block of mass 6 kg is being pulled by force 24 N as shown. If coefficient of friction between block and the surface is 0.6, frictional force acting on the block is A.36 N B.32 NC.12 N D.none of these
Solution
To find the frictional force acting on the block, we first need to calculate the force of gravity acting on the block. This is given by the equation:
Force of gravity = mass * acceleration due to gravity
Assuming the acceleration due to gravity is 9.8 m/s² (a standard value), the force of gravity is:
Force of gravity = 6 kg * 9.8 m/s² = 58.8 N
The frictional force is then given by the equation:
Frictional force = coefficient of friction * force of gravity
Substituting the given values:
Frictional force = 0.6 * 58.8 N = 35.28 N
So, the frictional force acting on the block is approximately 35.28 N. Therefore, the correct answer is D. None of these.
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