A block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless,horizontal table by a constant applied force of magnitude F = 16.0 N directed at anangle θ = 25.0° below the horizontal. Determine the work done on the block by:(a) the applied force.(b) the normal force exerted by the table.(c) the gravitational force.(d) the net force on the block.
Question
A block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless,horizontal table by a constant applied force of magnitude F = 16.0 N directed at anangle θ = 25.0° below the horizontal. Determine the work done on the block by:(a) the applied force.(b) the normal force exerted by the table.(c) the gravitational force.(d) the net force on the block.
Solution
To determine the work done on the block by different forces, we can use the formula:
Work = Force * Distance * cos(θ)
where:
- Force is the magnitude of the force applied,
- Distance is the distance over which the force is applied,
- θ is the angle between the force and the direction of motion.
(a) The work done by the applied force can be calculated as follows:
- Force = 16.0 N
- Distance = 2.20 m
- θ = 25.0°
Using the formula, we have: Work = 16.0 N * 2.20 m * cos(25.0°)
Calculating this expression will give us the work done by the applied force.
(b) The normal force exerted by the table does not do any work on the block because it is perpendicular to the direction of motion. Therefore, the work done by the normal force is zero.
(c) The gravitational force can be calculated using the formula: Gravitational force = mass * acceleration due to gravity
- Mass (m) = 2.50 kg
- Acceleration due to gravity (g) = 9.8 m/s^2
Using the formula, we have: Gravitational force = 2.50 kg * 9.8 m/s^2
(d) The net force on the block can be calculated by resolving the applied force into its horizontal and vertical components. The horizontal component of the force will contribute to the net force, while the vertical component will be balanced by the normal force.
To find the horizontal component of the force, we can use the formula: Horizontal force = Force * cos(θ)
Using the given values, we have: Horizontal force = 16.0 N * cos(25.0°)
Calculating this expression will give us the horizontal component of the force, which is the net force acting on the block.
By following these steps, you can determine the work done on the block by the applied force, the normal force, the gravitational force, and the net force.
Similar Questions
A row of blocks are lined up with masses of 1.26 kg, 2.16 kg and 4.34 kg. The masses are then pushed forward by a 19.3 N force applied to the 1.26 kg block. If the table is frictionless, how much force does the 2.16 kg block exert on the 4.34 kg block? 1.74 N 5.37 N 0.868 N 10.8 N
A force of 20 N is applied to push a block across a horizontal floor for a distance of 5 m. If the force is applied at an angle of 30 degrees to the horizontal, calculate the work done.
A person pushes a block of mass M = 6.0 kg with a constant speed of 5.0 m/s straight up along a flat surface inclined 30.0° above the horizontal. The coefficient of kinetic friction between the block and the surface is μ = 0.40. What is the net force acting on the block?
A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60∘ by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is : [g=10 m/s2]
Two blocks of masses m = 2 kg and M = 5 kg are in contact on a frictionless table. A horizontal force F = 35 N is applied to m. What is the force of contact between blocks ?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.