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Two blocks of masses m = 2 kg and M = 5 kg are in contact on a frictionless table. A horizontal force F = 35 N is applied to m. What is the force of contact between blocks ?

Question

Two blocks of masses m = 2 kg and M = 5 kg are in contact on a frictionless table. A horizontal force F = 35 N is applied to m. What is the force of contact between blocks ?

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Solution

To find the force of contact between the blocks, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Step 1: Identify the forces acting on the system. In this case, the only external force acting on the system is the applied force F = 35 N on block m.

Step 2: Determine the acceleration of the system. Since the table is frictionless, the only force causing acceleration is the applied force F. We can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

For block m: F = ma 35 N = 2 kg * a a = 35 N / 2 kg a = 17.5 m/s^2

Step 3: Calculate the force of contact between the blocks. Since the blocks are in contact and there is no friction, they will have the same acceleration. Therefore, the force of contact between the blocks will be equal in magnitude and opposite in direction to the force applied on block m.

The force of contact between the blocks is equal to the applied force F, which is 35 N.

This problem has been solved

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