A force, F = 14 N is applied on 5 kg block placed on smooth horizontal surface. Normal reaction acting between the blocks, is ______ N.
Question
A force, F = 14 N is applied on 5 kg block placed on smooth horizontal surface. Normal reaction acting between the blocks, is ______ N.
Solution
The normal force is the force exerted by a surface that supports the weight of an object resting on it. It acts perpendicular (or "normal") to the surface. The normal force is equal to the weight of the object, but in the opposite direction.
In this case, the weight of the block is its mass times the acceleration due to gravity.
Step 1: Identify the mass of the block, which is given as 5 kg.
Step 2: Identify the acceleration due to gravity. On Earth, this is approximately 9.8 m/s².
Step 3: Multiply the mass of the block by the acceleration due to gravity to find the weight of the block.
Weight = mass x gravity Weight = 5 kg x 9.8 m/s² = 49 N
Step 4: The normal force is equal to the weight of the block, but in the opposite direction. So, the normal force acting on the block is 49 N.
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