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Factor completely.3, x, squared, plus, 11, x, minus, 43x 2 +11x−4

Question

Factor completely.3, x, squared, plus, 11, x, minus, 43x 2 +11x−4

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Solution

The expression you provided seems to be a bit unclear, but I'm assuming you're asking to factor the quadratic equation 3x^2 + 11x - 4. Here's how you can do it:

Step 1: Write down the quadratic equation: 3x^2 + 11x - 4 = 0

Step 2: Find two numbers that multiply to (3*-4)=-12 and add up to 11. Those numbers are 12 and -1.

Step 3: Rewrite the middle term of the quadratic equation as the sum of the terms 12x and -1x: 3x^2 + 12x - 1x - 4 = 0

Step 4: Factor by grouping: 3x(x + 4) - 1(x + 4) = 0

Step 5: Notice that (x + 4) is a common factor. Factor it out: (x + 4)(3x - 1) = 0

So, the factored form of the equation 3x^2 + 11x - 4 = 0 is (x + 4)(3x - 1) = 0.

This problem has been solved

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