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Factor completely.4, x, squared, minus, 12, x, plus, 54x 2 −12x+5

Question

Factor completely.4, x, squared, minus, 12, x, plus, 54x 2 −12x+5

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Solution

The expression you provided seems to be a bit unclear. However, if you're asking to factor the quadratic equation 4x^2 - 12x + 5, here are the steps:

  1. Identify the coefficients of the quadratic equation. In this case, a = 4, b = -12, and c = 5.

  2. To factorize the quadratic equation, we need to find two numbers that add up to b (which is -12 in this case) and multiply to ac (which is 4*5 = 20 in this case).

  3. The two numbers that satisfy these conditions are -10 and -2 because -10*-2 = 20 and -10 + -2 = -12.

  4. Rewrite the middle term of the quadratic equation as the sum of the products of a and the two numbers found in step 3. This gives us: 4x^2 -10x -2x + 5.

  5. Factor by grouping: 2x(2x - 5) - 1(2x - 5).

  6. Now, you can see that (2x - 5) is a common factor. So, the completely factored form of the equation is: (2x - 5)(2x - 1).

So, the factored form of 4x^2 - 12x + 5 is (2x - 5)(2x - 1).

This problem has been solved

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