Factor completely.4, x, squared, minus, 1214x 2 −121
Question
Factor completely.4, x, squared, minus, 1214x 2 −121
Solution
The expression you provided seems to have a typo. If you meant "4x^2 - 121", then here's how to factor it:
This is a difference of squares, which can be factored as follows:
4x^2 - 121 = (2x)^2 - 11^2
This can be factored into:
(2x - 11)(2x + 11)
So, 4x^2 - 121 = (2x - 11)(2x + 11) is the factored form of the expression.
Similar Questions
Factor completely.100, x, squared, minus, 121100x 2 −121
Factor completely.4, x, squared, minus, 12, x, minus, 1604x 2 −12x−160
Factor completely.4, x, squared, minus, 12, x, plus, 54x 2 −12x+5
Factor completely.4, x, squared, minus, 4, x, plus, 14x 2 −4x+1
Factor completely.4, minus, x, squared4−x 2
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.