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Factor completely.6, x, squared, plus, 13, x, minus, 56x 2 +13x−5

Question

Factor completely.6, x, squared, plus, 13, x, minus, 56x 2 +13x−5

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Solution

The expression you provided seems to have a typo. It should probably be "6x^2 + 13x - 5". Here's how to factor it:

  1. First, we need to find two numbers that multiply to (6*-5)=-30 and add to 13. Those numbers are 15 and -2.

  2. Rewrite the middle term of the quadratic equation, splitting it into 15x and -2x: 6x^2 + 15x - 2x - 5.

  3. Factor by grouping: 3x(2x + 5) -1(2x + 5).

  4. Since (2x + 5) is a common factor, we can write the expression as: (3x - 1)(2x + 5).

So, the factored form of 6x^2 + 13x - 5 is (3x - 1)(2x + 5).

This problem has been solved

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