Factor completely.5, x, squared, minus, 8, x, plus, 35x 2 −8x+3

It seems like there might be a mistake in your question. The expression "5, x, squared, minus, 8, x, plus, 35x 2 −8x+3" is not clear. Could you please rephrase it or provide it in a standard mathematical format? For example, "5x^2 - 8x + 3".

It seems like there might be a mistake in your question. The expression you provided "5, x, squared, minus, 8, x, plus, 35x 2 −8x+3" is not clear.

If you meant "5x^2 - 8x + 3", then here's how to factor it:

Unfortunately, this quadratic equation cannot be factored using integers because its discriminant (b^2 - 4ac) is negative. The discriminant is calculated as follows:

Discriminant = (-8)^2 - 453 = 64 - 60 = 4

Since the discriminant is positive, the equation can be factored. However, the roots of the equation (which are the solutions to the equation 5x^2 - 8x + 3 = 0) are not integers. They can be found using the quadratic formula:

x = [8 ± sqrt(4)] / (2*5) x = [8 ± 2] / 10 x = 1 or x = 0.6

So, the factored form of the equation using the roots is:

5(x - 1)(x - 0.6)

Please check your equation and try again.