Factor completely.3, x, squared, plus, 8, x, plus, 53x 2 +8x+5

The expression you provided seems to be a bit confusing. However, if you're asking to factor the quadratic equation 3x^2 + 8x + 5, here are the steps:

1. Identify the coefficients a, b, and c in the quadratic equation ax^2 + bx + c. In this case, a = 3, b = 8, and c = 5.

2. Check if the equation can be factored. For this, calculate the discriminant using the formula b^2 - 4ac. If the discriminant is less than 0, the equation cannot be factored using real numbers.

3. In this case, the discriminant is 8^2 - 435 = 64 - 60 = 4, which is greater than 0. So, the equation can be factored.

4. Find two numbers that multiply to give ac (which is 15) and add to give b (which is 8). The numbers are 5 and 3.

5. Rewrite the equation by splitting the middle term: 3x^2 + 5x + 3x + 5.

6. Factor by grouping: x(3x + 5) + 1(3x + 5).

7. Since the terms in parentheses are the same, you can factor them out to get the final factored form of the equation: (3x + 5)(x + 1).

So, the factored form of the equation 3x^2 + 8x + 5 is (3x + 5)(x + 1).