In a box, there are 8 orange, 7 white, and 6 blue balls. If a ball is picked up randomly, what is the probability that it is neither orange nor blue?Options 13 221 521
Question
In a box, there are 8 orange, 7 white, and 6 blue balls. If a ball is picked up randomly, what is the probability that it is neither orange nor blue?Options 13 221 521
Solution
The total number of balls is 8 (orange) + 7 (white) + 6 (blue) = 21 balls.
The event of picking a ball that is neither orange nor blue is the same as picking a white ball.
There are 7 white balls.
So, the probability is the number of favorable outcomes (picking a white ball) divided by the total number of outcomes (total balls).
Therefore, the probability is 7 (white balls) / 21 (total balls) = 1/3.
So, the correct option is not listed in your options.
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