A box contains 8 red balls, 6 blue balls, and 4 green balls. If one ball is picked at random, what is the probability that it is either red or green? *1/25/97/93/4
Question
A box contains 8 red balls, 6 blue balls, and 4 green balls. If one ball is picked at random, what is the probability that it is either red or green? *1/25/97/93/4
Solution
To solve this problem, we first need to determine the total number of balls and the number of favorable outcomes.
Step 1: Determine the total number of balls. The box contains 8 red balls, 6 blue balls, and 4 green balls. So, the total number of balls is 8 + 6 + 4 = 18 balls.
Step 2: Determine the number of favorable outcomes. We are looking for the probability of drawing either a red or a green ball. There are 8 red balls and 4 green balls, so there are 8 + 4 = 12 favorable outcomes.
Step 3: Calculate the probability. The probability of an event is given by the ratio of the number of favorable outcomes to the total number of outcomes. So, the probability of drawing either a red or a green ball is 12/18 = 2/3.
So, the probability that the ball drawn is either red or green is 2/3.
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