In a box, there are 7 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?AnswerPlease choose a correct answer. CLEARUNSOLVED2/31/61/31/ 4
Question
In a box, there are 7 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?AnswerPlease choose a correct answer. CLEARUNSOLVED2/31/61/31/ 4
Solution
The total number of balls is 7 (red) + 6 (blue) + 5 (green) = 18 balls.
The event of picking a ball that is neither red nor green is the same as the event of picking a blue ball.
There are 6 blue balls, so the probability of this event is 6 (favorable outcomes) divided by 18 (total outcomes).
So, the probability is 6/18 = 1/3.
Therefore, the correct answer is 1/3.
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