ProbabilityIn a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?Options1/31/62/34/5

To solve this problem, we first need to understand the total number of balls and the number of balls that are neither red nor green.

Step 1: Calculate the total number of balls The total number of balls is the sum of red, blue, and green balls. That is 8 (red) + 7 (blue) + 6 (green) = 21 balls.

Step 2: Identify the number of balls that are neither red nor green The balls that are neither red nor green are the blue balls. There are 7 blue balls.

Step 3: Calculate the probability The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes. In this case, the favorable outcome is picking a blue ball, and the total number of outcomes is the total number of balls.

So, the probability of picking a blue ball is 7 (blue balls) / 21 (total balls) = 1/3.

Therefore, the probability that the ball picked up is neither red nor green is 1/3.