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4x+7y=−238, x, plus, 5, y, equals, minus, 18x+5y=−1

Question

4x+7y=−238, x, plus, 5, y, equals, minus, 18x+5y=−1

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Solution

It seems like you have two equations here and you want to solve for x and y. The equations are:

  1. 4x + 7y = -238
  2. 18x + 5y = -1

This is a system of linear equations. You can solve it using substitution or elimination method. Here, I'll use the elimination method.

First, let's multiply the first equation by 5 and the second equation by 7 to make the coefficients of y the same in both equations:

  1. 20x + 35y = -1190
  2. 126x + 35y = -7

Now, subtract the second equation from the first:

-106x = -1183

Divide both sides by -106 to solve for x:

x = 1183 / 106 = 11.16 (rounded to two decimal places)

Now, substitute x = 11.16 into the first equation:

4(11.16) + 7y = -238 44.64 + 7y = -238 7y = -238 - 44.64 7y = -282.64 y = -282.64 / 7 y = -40.38 (rounded to two decimal places)

So, the solution to the system of equations is x = 11.16 and y = -40.38.

This problem has been solved

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