4x+7y=−238, x, plus, 5, y, equals, minus, 18x+5y=−1
Question
4x+7y=−238, x, plus, 5, y, equals, minus, 18x+5y=−1
Solution
It seems like you have two equations here and you want to solve for x and y. The equations are:
- 4x + 7y = -238
- 18x + 5y = -1
This is a system of linear equations. You can solve it using substitution or elimination method. Here, I'll use the elimination method.
First, let's multiply the first equation by 5 and the second equation by 7 to make the coefficients of y the same in both equations:
- 20x + 35y = -1190
- 126x + 35y = -7
Now, subtract the second equation from the first:
-106x = -1183
Divide both sides by -106 to solve for x:
x = 1183 / 106 = 11.16 (rounded to two decimal places)
Now, substitute x = 11.16 into the first equation:
4(11.16) + 7y = -238 44.64 + 7y = -238 7y = -238 - 44.64 7y = -282.64 y = -282.64 / 7 y = -40.38 (rounded to two decimal places)
So, the solution to the system of equations is x = 11.16 and y = -40.38.
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