A snooker ball of mass 0.20 kg has a collision so that its direction of movement changes by anangle of 90°, as shown.0.40 m s –10.30 m s –1before the collision after the collisionsnooker ball,mass 0.20 kgThe ball has a speed of 0.40 m s –1 before the collision and a speed of 0.30 m s –1 after the collision.What is the magnitude of the change in momentum of the snooker ball?A 0.020 kg m s–1B 0.10 kg m s –1C 0.14 kg m s –1D 0.50 kg m s –1
Question
A snooker ball of mass 0.20 kg has a collision so that its direction of movement changes by anangle of 90°, as shown.0.40 m s –10.30 m s –1before the collision after the collisionsnooker ball,mass 0.20 kgThe ball has a speed of 0.40 m s –1 before the collision and a speed of 0.30 m s –1 after the collision.What is the magnitude of the change in momentum of the snooker ball?A 0.020 kg m s–1B 0.10 kg m s –1C 0.14 kg m s –1D 0.50 kg m s –1
Solution
The momentum of an object is given by the product of its mass and velocity. The change in momentum (also known as impulse) is given by the difference between the final and initial momentum. However, because the direction of the ball changes, we can't simply subtract the initial momentum from the final momentum. We have to use vector subtraction.
The initial momentum (p1) is mass * velocity = 0.20 kg * 0.40 m/s = 0.08 kg*m/s.
The final momentum (p2) is mass * velocity = 0.20 kg * 0.30 m/s = 0.06 kg*m/s.
These two momenta form a right angle with each other, so we can use the Pythagorean theorem to find the resultant (the change in momentum):
|Δp| = sqrt((p1)^2 + (p2)^2) = sqrt((0.08 kgm/s)^2 + (0.06 kgm/s)^2) = sqrt((0.0064 kg^2m^2/s^2) + (0.0036 kg^2m^2/s^2)) = sqrt(0.01 kg^2m^2/s^2) = 0.10 kgm/s.
So, the magnitude of the change in momentum of the snooker ball is 0.10 kg*m/s, which corresponds to option B.
Similar Questions
Alex throws a 0.43-kg rubber ball down onto the floor. The ball's speed just before impact is 6.5 m/s, and just after is 5.5 m/s. What is the magnitude of the change in the ball's momentum?Select one:a.1.0 kgm/sb.5.2 kgm/sc.4.3 kgm/sd.0.09 kgm/s
A 0.10-kg ball is moving at 5 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 12 m/s. What is the change in the magnitude of the momentum of the ball?Select one:a.0.7 kg⋅m/sb.1.7 kg⋅m/sc.7 kg⋅m/sd.1.2 kg⋅m/se.0.5 kg⋅m/s
Jerome pitches a baseball of mass 0.15 kg. The ball arrives at home plate with a speed of 45 m/s and is batted straight back to Jerome with a return speed of 65 m/s. What is the magnitude of change in the ball's momentum?Select one:a.16.5 kg⋅m/sb.20 kg⋅m/sc.3 kg⋅m/sd.9.75 kg⋅m/se.6.75 kg⋅m/s
A tennis ball of mass 50g is hit against a wall. It hits the wall going right at 5 ms-1 and rebounds to the left at 4 ms-1.What is the change in momentum of the tennis ball?Question 1Select one:a.0.45 kg m/s rightb.0.05 kg m/s rightc.45 kg m/s leftd.0.05 kg m/s lefte.0.45 kg m/s leftClear my choiceCheckQuestion 1
A billiard ball is moving in the x direction at 40.0 cm/s and strikes another billiard ball moving in the y direction at 30.0 cm/s. As a result of the collision, the first ball moves at 50.0 cm/s, and the second ball stops. What is the change in kinetic energy of the system as a result of the collision?Select one:a.some negative valueb.some positive valuec.No answer above is correct.d.0
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.