A 0.10-kg ball is moving at 5 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 12 m/s. What is the change in the magnitude of the momentum of the ball?Select one:a.0.7 kg⋅m/sb.1.7 kg⋅m/sc.7 kg⋅m/sd.1.2 kg⋅m/se.0.5 kg⋅m/s
Question
A 0.10-kg ball is moving at 5 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 12 m/s. What is the change in the magnitude of the momentum of the ball?Select one:a.0.7 kg⋅m/sb.1.7 kg⋅m/sc.7 kg⋅m/sd.1.2 kg⋅m/se.0.5 kg⋅m/s
Solution
The change in momentum (Δp) can be calculated using the formula:
Δp = m * Δv
where: m is the mass of the object, and Δv is the change in velocity.
Here, the mass of the ball (m) is 0.10 kg. The initial velocity of the ball is 5 m/s, and the final velocity is -12 m/s (the negative sign indicates that the direction of the velocity has reversed).
So, the change in velocity (Δv) is:
Δv = final velocity - initial velocity Δv = -12 m/s - 5 m/s Δv = -17 m/s
Now, we can calculate the change in momentum:
Δp = m * Δv Δp = 0.10 kg * -17 m/s Δp = -1.7 kg*m/s
However, since the question asks for the change in the magnitude of the momentum (which is always a positive value), we take the absolute value of Δp:
|Δp| = 1.7 kg*m/s
So, the change in the magnitude of the momentum of the ball is 1.7 kgm/s. Therefore, the correct answer is (b) 1.7 kgm/s.
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