A tennis ball of mass 50g is hit against a wall. It hits the wall going right at 5 ms-1 and rebounds to the left at 4 ms-1.What is the change in momentum of the tennis ball?Question 1Select one:a.0.45 kg m/s rightb.0.05 kg m/s rightc.45 kg m/s leftd.0.05 kg m/s lefte.0.45 kg m/s leftClear my choiceCheckQuestion 1
Question
A tennis ball of mass 50g is hit against a wall. It hits the wall going right at 5 ms-1 and rebounds to the left at 4 ms-1.What is the change in momentum of the tennis ball?Question 1Select one:a.0.45 kg m/s rightb.0.05 kg m/s rightc.45 kg m/s leftd.0.05 kg m/s lefte.0.45 kg m/s leftClear my choiceCheckQuestion 1
Solution
The change in momentum (Δp) of an object can be calculated using the formula:
Δp = m * Δv
where: m is the mass of the object, and Δv is the change in velocity of the object.
In this case, the mass (m) of the tennis ball is 50g, which is equal to 0.05 kg (since 1g = 0.001 kg).
The initial velocity (v1) of the tennis ball is 5 m/s to the right. Since the ball rebounds to the left, we can consider this direction as negative. Therefore, the final velocity (v2) of the ball is -4 m/s.
The change in velocity (Δv) is therefore:
Δv = v2 - v1 Δv = -4 m/s - 5 m/s Δv = -9 m/s
Substituting these values into the formula for change in momentum gives:
Δp = m * Δv Δp = 0.05 kg * -9 m/s Δp = -0.45 kg*m/s
The negative sign indicates that the change in momentum is to the left. Therefore, the change in momentum of the tennis ball is 0.45 kg*m/s to the left. So, the correct answer is e. 0.45 kg m/s left.
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