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Alex throws a 0.43-kg rubber ball down onto the floor. The ball's speed just before impact is 6.5 m/s, and just after is 5.5 m/s. What is the magnitude of the change in the ball's momentum?Select one:a.1.0 kgm/sb.5.2 kgm/sc.4.3 kgm/sd.0.09 kgm/s

Question

Alex throws a 0.43-kg rubber ball down onto the floor. The ball's speed just before impact is 6.5 m/s, and just after is 5.5 m/s. What is the magnitude of the change in the ball's momentum?Select one:a.1.0 kgm/sb.5.2 kgm/sc.4.3 kgm/sd.0.09 kgm/s

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Solution

The momentum of an object is calculated by the product of its mass and velocity. The change in momentum (also known as impulse) is calculated by the difference in final momentum and initial momentum.

The initial momentum (before impact) can be calculated as: Initial momentum = mass * initial velocity = 0.43 kg * 6.5 m/s = 2.795 kgm/s

The final momentum (after impact) can be calculated as: Final momentum = mass * final velocity = 0.43 kg * 5.5 m/s = 2.365 kgm/s

The change in momentum is the absolute difference between the final and initial momenta: Change in momentum = |Final momentum - Initial momentum| = |2.365 kgm/s - 2.795 kgm/s| = 0.43 kgm/s

So, the magnitude of the change in the ball's momentum is 0.43 kgm/s. Therefore, the correct answer is c. 0.43 kgm/s.

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