Dilute ethanoic acid reacts with sodium carbonate.2CH 3 COOH + Na2 CO3 2CH 3 COONa + H2 O + CO2Calculate the volume, measured at r.t.p., of carbon dioxide produced, in cm 3 , when 3.18 g ofsodium carbonate reacts with excess dilute ethanoic acid.volume of carbon dioxide .................................................. cm3
Question
Dilute ethanoic acid reacts with sodium carbonate.2CH 3 COOH + Na2 CO3 2CH 3 COONa + H2 O + CO2Calculate the volume, measured at r.t.p., of carbon dioxide produced, in cm 3 , when 3.18 g ofsodium carbonate reacts with excess dilute ethanoic acid.volume of carbon dioxide .................................................. cm3
Solution
To solve this problem, we need to follow these steps:
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First, we need to find the molar mass of sodium carbonate (Na2CO3). The molar mass of Na is approximately 23 g/mol, C is approximately 12 g/mol, and O is approximately 16 g/mol. So, the molar mass of Na2CO3 is (223) + 12 + (316) = 106 g/mol.
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Next, we calculate the number of moles of sodium carbonate in 3.18 g. We do this by dividing the mass by the molar mass. So, 3.18 g / 106 g/mol = 0.03 mol.
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The balanced chemical equation shows that one mole of sodium carbonate produces one mole of carbon dioxide. Therefore, 0.03 mol of sodium carbonate will produce 0.03 mol of carbon dioxide.
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At room temperature and pressure (r.t.p.), one mole of any gas occupies 24,000 cm3. Therefore, 0.03 mol of carbon dioxide will occupy 0.03 * 24,000 cm3 = 720 cm3.
So, the volume of carbon dioxide produced when 3.18 g of sodium carbonate reacts with excess dilute ethanoic acid is 720 cm3.
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