Sodium carbonate on reaction with hydrochloric acid in equalmolar concentrations gives sodium chloride and sodiumhydrogencarbonate
Question
Sodium carbonate on reaction with hydrochloric acid in equalmolar concentrations gives sodium chloride and sodiumhydrogencarbonate
Solution
The reaction you're referring to seems to be a bit incorrect. Sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCl) to produce sodium chloride (NaCl) and carbonic acid (H2CO3), not sodium bicarbonate. The reaction is as follows:
Na2CO3 + 2HCl -> 2NaCl + H2CO3
The carbonic acid then decomposes into water and carbon dioxide:
H2CO3 -> H2O + CO2
So, the overall reaction is:
Na2CO3 + 2HCl -> 2NaCl + H2O + CO2
This is a type of double displacement reaction, where the sodium (Na) and hydrogen (H) ions switch places.
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Using the background theory provided, choose the set of equations that best describe the reaction between the sodium carbonate and hydrochloric acid in experiment 1.Question 2Select one:a. (1) Na2CO3 (s) → 2Na+ (aq) + CO32- (aq) (2) HCl (g) → H+ (aq) + Cl- (aq) (3) 2H+ (aq) + CO32- (aq) → H2CO3 (aq) (4) H2CO3 (aq) → CO2 (g) + H2O (l) b. (1) HCl (g) → H+ (aq) + Cl- (aq) (2) NaHCO3 (aq) → Na+ (aq) + HCO3- (aq) c. (1) HCl (g) → H+ (aq) + Cl- (aq) (2) NaOH (s) → Na+ + OH- (3) Na+ (aq) + OH- (aq) + H+ (aq) + Cl- (aq) → NaCl (aq) + H2O (aq) d. (1) Na2CO3 (s) → Na+ (aq) + CO3- (aq) (2) HCl (g) → H+ (aq) + Cl- (aq) (3) H+ (aq) + CO3- (aq) → HCO3- (aq)
1. In an experiment, 0.933 g of a sample of washing soda (Na2CO3. xH2O) wasdissolved in some distilled water. The solution was treated against 0.258 Mhydrochloric acid. 25.4 cm3 of the acid was required for the completion of thefollowing reaction:Na2CO3 + 2HCl → 2NaCl + H2O + CO2i. From the result, calculate the number of moles of sodium carbonate in thesample of washing soda
Indicate whether each species is a reactant, product or spectator.Dilute hydrochloric acid is added to a solution of sodium carbonate, evolving carbon dioxide.2H+(aq) + 2Cl-(aq) + 2Na+(aq) + CO32-(aq) → CO2(g) + H2O(l) + 2Na+(aq) + 2Cl-(aq)
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