Calculate the volume, measured at r.t.p., of carbon dioxide produced, in cm 3 , when 2.65 g ofsodium carbonate reacts with excess hydrochloric acid.2HCl + Na2 CO3 2NaCl + H2 O + CO2
Question
Calculate the volume, measured at r.t.p., of carbon dioxide produced, in cm 3 , when 2.65 g ofsodium carbonate reacts with excess hydrochloric acid.2HCl + Na2 CO3 2NaCl + H2 O + CO2
Solution
Sure, here are the steps to calculate the volume of carbon dioxide produced:
Step 1: Calculate the molar mass of sodium carbonate (Na2CO3). The molar mass of Na is approximately 23 g/mol, C is approximately 12 g/mol, and O is approximately 16 g/mol. So, the molar mass of Na2CO3 is (223) + 12 + (316) = 106 g/mol.
Step 2: Calculate the number of moles of sodium carbonate. The number of moles is given by the mass of the substance divided by its molar mass. So, the number of moles of sodium carbonate is 2.65 g / 106 g/mol = 0.025 moles.
Step 3: From the balanced chemical equation, we can see that one mole of sodium carbonate reacts to produce one mole of carbon dioxide. Therefore, the number of moles of carbon dioxide produced is also 0.025 moles.
Step 4: At room temperature and pressure (r.t.p.), one mole of any gas occupies a volume of 24,000 cm^3. Therefore, the volume of carbon dioxide produced is 0.025 moles * 24,000 cm^3/mol = 600 cm^3.
So, the volume of carbon dioxide produced when 2.65 g of sodium carbonate reacts with excess hydrochloric acid is 600 cm^3.
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