5.00 dm3 of ethane reacts with 5.00 dm3 of oxygen according to the reaction below. Calculate the volume of carbon dioxide that is produced in the reaction. 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)All gas volumes are measured under the same conditions of temperature and pressure.
Question
5.00 dm3 of ethane reacts with 5.00 dm3 of oxygen according to the reaction below. Calculate the volume of carbon dioxide that is produced in the reaction. 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)All gas volumes are measured under the same conditions of temperature and pressure.
Solution
The balanced chemical equation shows that 2 moles of ethane (C2H6) react with 7 moles of oxygen (O2) to produce 4 moles of carbon dioxide (CO2).
Given that the volumes of gases are proportional to the number of moles of the gases (according to Avogadro's law), we can set up the following ratio:
2 : 7 : 4 (C2H6 : O2 : CO2)
This means that for every 2 volumes of ethane, 4 volumes of carbon dioxide are produced.
In this case, we have 5.00 dm3 of ethane reacting, so we can set up a proportion to find the volume of CO2 produced:
2/4 = 5/x
Solving for x gives x = 10.00 dm3.
Therefore, 10.00 dm3 of carbon dioxide is produced in the reaction.
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