Monochromatic light of frequency 6×1014 Hz is produced by a laser. The power emitted is 2×10−3 W(i) What is the energy of the photon in the light beam?(ii) How many photons per second, on an average are emitted by the source ?
Question
Monochromatic light of frequency 6×1014 Hz is produced by a laser. The power emitted is 2×10−3 W(i) What is the energy of the photon in the light beam?(ii) How many photons per second, on an average are emitted by the source ?
Solution
(i) The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.63 x 10^-34 Js) and f is the frequency of the light.
So, E = (6.63 x 10^-34 Js) x (6 x 10^14 Hz) = 3.978 x 10^-19 Joules.
(ii) The number of photons per second (also known as the photon flux) can be calculated by dividing the total power P by the energy per photon E.
So, the number of photons per second = P/E = (2 x 10^-3 W) / (3.978 x 10^-19 Joules) = 5.03 x 10^15 photons per second.
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