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What is the energy (in eV) of a photon in a monochromatic beam of light with a wavelength of 325.0325.0 nm? (Give your answer to two decimal places)

Question

What is the energy (in eV) of a photon in a monochromatic beam of light with a wavelength of 325.0325.0 nm? (Give your answer to two decimal places)

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Solution

The energy of a photon can be calculated using the formula:

E = hc/λ

where: E is the energy of the photon, h is Planck's constant (4.135667696 x 10^-15 eV.s), c is the speed of light (299792458 m/s), and λ is the wavelength of the light.

First, we need to convert the wavelength from nanometers to meters. 1 nm = 10^-9 m, so:

λ = 325.0 nm = 325.0 x 10^-9 m = 3.25 x 10^-7 m

Now we can substitute the values into the formula:

E = (4.135667696 x 10^-15 eV.s x 299792458 m/s) / 3.25 x 10^-7 m E = 3.82 eV

So, the energy of a photon in a monochromatic beam of light with a wavelength of 325.0 nm is approximately 3.82 eV.

This problem has been solved

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