What is the wavelength of a photon with an energy of 3.38 𝑥x 10-19 J?A.460 nmB.416 nmC.588 nmD.510 nm

To find the wavelength of a photon, we can use the equation that relates energy (E), wavelength (λ), and the speed of light (c):

E = hc/λ

where:

• E is the energy of the photon,
• h is Planck's constant (6.63 x 10^-34 J*s),
• c is the speed of light (3.00 x 10^8 m/s),
• λ is the wavelength we want to find.

We can rearrange this equation to solve for λ:

λ = hc/E

Substituting the given values:

λ = (6.63 x 10^-34 J*s * 3.00 x 10^8 m/s) / 3.38 x 10^-19 J

Solving this equation will give us the wavelength in meters. To convert to nanometers (nm), we multiply by 10^9.

After calculating, we can compare the result with the options given to find the correct answer.

To find the wavelength of a photon, we can use the equation that relates energy of a photon to its wavelength:

E = hc/λ

where: E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength.

We are given E = 3.38 x 10^-19 J and we need to find λ.

Rearranging the equation for λ gives:

λ = hc/E

Substituting the given values and constants into the equation gives:

λ = (6.626 x 10^-34 J.s * 3.00 x 10^8 m/s) / 3.38 x 10^-19 J

Solving this equation gives λ = 5.88 x 10^-7 m, or 588 nm.

So, the correct answer is C. 588 nm.

To find the wavelength of a photon, we can use the equation that relates energy (E), wavelength (λ), and Planck's constant (h):

E = h * c / λ

where:

• E is the energy of the photon (3.38 x 10^-19 J),
• h is Planck's constant (6.626 x 10^-34 J*s),
• c is the speed of light (3.00 x 10^8 m/s), and
• λ is the wavelength we want to find.

We can rearrange the equation to solve for λ:

λ = h * c / E

Substituting the given values:

λ = (6.626 x 10^-34 J*s * 3.00 x 10^8 m/s) / 3.38 x 10^-19 J

Solving this equation will give us the wavelength in meters. To convert it to nanometers (nm), we multiply the result by 10^9 (since 1 m = 10^9 nm).

After performing the calculation, we can compare the result with the options given (A. 460 nm, B. 416 nm, C. 588 nm, D. 510 nm) to find the correct answer.