The energy of incident photons corresponding to the maximum wavelength of visible light is:3.2 eV7 eV1.6 eV1 eV

The energy of a photon can be calculated using the formula:

E = hc/λ

where: E is the energy of the photon, h is Planck's constant (approximately 6.626 x 10^-34 Joule seconds), c is the speed of light (approximately 3.00 x 10^8 meters per second), λ is the wavelength of the light.

The maximum wavelength of visible light is about 700 nanometers (nm), or 700 x 10^-9 meters.

First, convert the energy from electron volts (eV) to Joules (J), since Planck's constant is in Joules. 1 eV is approximately 1.602 x 10^-19 Joules.

Now, plug the values into the formula:

E = (6.626 x 10^-34 J*s) * (3.00 x 10^8 m/s) / (700 x 10^-9 m) E = 2.84 x 10^-19 J

Convert this energy back to electron volts:

E = (2.84 x 10^-19 J) / (1.602 x 10^-19 J/eV) E = 1.77 eV

So, the energy of incident photons corresponding to the maximum wavelength of visible light is closest to 1.6 eV from the given options.