To solve this problem, we need to use the formula for the energy of a photon, which is given by E = hf, where h is Planck's constant and f is the frequency of the light.

Step 1: Calculate the energy of one photon
The frequency f is given as 6×10^14 Hz. Planck's constant h is approximately 6.63×10^-34 Js. So, the energy E of one photon is E = hf = (6.63×10^-34 Js)(6×10^14 Hz) = 3.978×10^-19 J.

Step 2: Calculate the number of photons per second
The power P emitted by the laser is the energy emitted per second, which is given as 4×10^-3 W = 4×10^-3 J/s. The number of photons emitted per second n is then given by n = P/E = (4×10^-3 J/s) / (3.978×10^-19 J/photon) = 1.005×10^16 photons/s.

So, the laser emits approximately 1.005×10^16 photons per second.

Question

To solve this problem, we need to use the formula for the energy of a photon, which is given by E = hf, where h is Planck's constant and f is the frequency of the light.

Step 1: Calculate the energy of one photon
The frequency f is given as 6×10^14 Hz. Planck's constant h is approximately 6.63×10^-34 Js. So, the energy E of one photon is E = hf = (6.63×10^-34 Js)(6×10^14 Hz) = 3.978×10^-19 J.

Step 2: Calculate the number of photons per second
The power P emitted by the laser is the energy emitted per second, which is given as 4×10^-3 W = 4×10^-3 J/s. The number of photons emitted per second n is then given by n = P/E = (4×10^-3 J/s) / (3.978×10^-19 J/photon) = 1.005×10^16 photons/s.

So, the laser emits approximately 1.005×10^16 photons per second.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for the energy of a photon, which is given by E = hf, where h is Planck's constant and f is the frequency of the light.

Step 1: Calculate the energy of one photon
The frequency f is given as 6×10^14 Hz. Planck's constant h is approximately 6.63×10^-34 Js. So, the energy E of one photon is E = hf = (6.63×10^-34 Js)(6×10^14 Hz) = 3.978×10^-19 J.

Step 2: Calculate the number of photons per second
The power P emitted by the laser is the energy emitted per second, which is given as 4×10^-3 W = 4×10^-3 J/s. The number of photons emitted per second n is then given by n = P/E = (4×10^-3 J/s) / (3.978×10^-19 J/photon) = 1.005×10^16 photons/s.

So, the laser emits approximately 1.005×10^16 photons per second.

Monochromatic light of frequency of 6×10^14 Hz is produced by a laser. Power emitted is 4×10−3W. Approximately how many photons per second are emitted by the source?

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