The energy of a photon can be calculated using the formula:

E = h * v

where:
E is the energy of the photon,
h is Planck's constant (6.63 x 10^-34 Joule seconds), and
v is the frequency of the light.

Given that the frequency v = 4.47 x 10^14 Hz, we can substitute these values into the formula:

E = (6.63 x 10^-34 J*s) * (4.47 x 10^14 Hz)

E = 2.96 x 10^-19 J

So, the energy of the photon that emits a light of frequency 4.47 x 10^14 Hz is 2.96 x 10^-19 J. Therefore, the correct answer is A. 2.96 x 10^-19 J.

Question

The energy of a photon can be calculated using the formula:

E = h * v

where:
E is the energy of the photon,
h is Planck's constant (6.63 x 10^-34 Joule seconds), and
v is the frequency of the light.

Given that the frequency v = 4.47 x 10^14 Hz, we can substitute these values into the formula:

E = (6.63 x 10^-34 J*s) * (4.47 x 10^14 Hz)

E = 2.96 x 10^-19 J

So, the energy of the photon that emits a light of frequency 4.47 x 10^14 Hz is 2.96 x 10^-19 J. Therefore, the correct answer is A. 2.96 x 10^-19 J.

Knowee AI · Accepted Answer

The energy of a photon can be calculated using the formula:

E = h * v

where:
E is the energy of the photon,
h is Planck's constant (6.63 x 10^-34 Joule seconds), and
v is the frequency of the light.

Given that the frequency v = 4.47 x 10^14 Hz, we can substitute these values into the formula:

E = (6.63 x 10^-34 J*s) * (4.47 x 10^14 Hz)

E = 2.96 x 10^-19 J

So, the energy of the photon that emits a light of frequency 4.47 x 10^14 Hz is 2.96 x 10^-19 J. Therefore, the correct answer is A. 2.96 x 10^-19 J.

What is the energy of a photon that emits a light of frequency 4.47 𝑥x 1014 Hz?A.2.96 𝑥x 10-19 JB.6.71 𝑥x 10-19 JC.1.34 𝑥x 10-19 JD.6.75 𝑥x 10-19 J