What is the wavelength of a photon with an energy of 3.38 𝑥x 10-19 J?A.416 nmB.460 nmC.510 nmD.588 nm
Question
What is the wavelength of a photon with an energy of 3.38 𝑥x 10-19 J?A.416 nmB.460 nmC.510 nmD.588 nm
Solution
To find the wavelength of a photon, we can use the equation that relates energy of a photon to its wavelength:
E = hc/λ
where: E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon.
We are given that E = 3.38 x 10^-19 J. We can rearrange the equation to solve for λ:
λ = hc/E
Substituting the given values:
λ = (6.63 x 10^-34 J.s * 3.00 x 10^8 m/s) / 3.38 x 10^-19 J
Solving this gives us a wavelength in meters. To convert to nanometers (nm), we multiply by 10^9 (since 1 m = 10^9 nm).
After calculating, we find that the wavelength is approximately 588 nm. So, the correct answer is D. 588 nm.
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