Calculate the volume in milliliters of a 3.71/molL potassium iodide solution that contains 150.g of potassium iodide KI. Round your answer to 3 significant digits.

Sure, here are the steps to calculate the volume:

1. First, we need to convert the mass of potassium iodide (KI) to moles. We do this using the molar mass of KI, which is approximately 166.00277 g/mol.

   Moles of KI = 150 g / 166.00277 g/mol = 0.903 moles (rounded to three decimal places)

2. Next, we use the molarity formula to find the volume. The molarity (M) is defined as the number of moles of solute (n) divided by the volume of the solution (V) in liters.

   M = n / V

   We can rearrange this formula to solve for V:

   V = n / M

3. Substituting the given molarity (3.71 mol/L) and the calculated moles of KI (0.903 moles) into the formula gives:

   V = 0.903 moles / 3.71 mol/L = 0.243 L

4. Finally, we convert the volume from liters to milliliters (since 1 L = 1000 mL):

   V = 0.243 L * 1000 mL/L = 243 mL

So, the volume of the 3.71 mol/L potassium iodide solution that contains 150 g of KI is approximately 243 mL.