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A 0.29 L solution of KClO3 is diluted from its original concentration of 3 M to a new concentration of 0.369 M. What is the resulting volume of the diluted solution?

Question

A 0.29 L solution of KClO3 is diluted from its original concentration of 3 M to a new concentration of 0.369 M. What is the resulting volume of the diluted solution?

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Solution

To solve this problem, we can use the formula for dilution: M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Given in the problem, we have:

M1 = 3 M (initial molarity) V1 = 0.29 L (initial volume) M2 = 0.369 M (final molarity) V2 = ? (final volume, which we're trying to find)

Substituting the given values into the formula, we get:

(3 M)(0.29 L) = (0.369 M)(V2)

Solving for V2, we get:

V2 = (3 M * 0.29 L) / 0.369 M

V2 = 2.36 L

So, the resulting volume of the diluted solution is 2.36 liters.

This problem has been solved

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