A chemist prepares a solution of potassium permanganate KMnO4 by measuring out 7.6mg of potassium permanganate into a 50.mL volumetric flask and filling the flask to the mark with water.Calculate the concentration in /molL of the chemist's potassium permanganate solution. Be sure your answer has the correct number of significant digits.
Question
A chemist prepares a solution of potassium permanganate KMnO4 by measuring out 7.6mg of potassium permanganate into a 50.mL volumetric flask and filling the flask to the mark with water.Calculate the concentration in /molL of the chemist's potassium permanganate solution. Be sure your answer has the correct number of significant digits.
Solution
To calculate the concentration of the solution, we first need to convert the mass of KMnO4 into moles.
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The molar mass of KMnO4 is approximately 158.034 g/mol. We have 7.6 mg of KMnO4, which is 0.0076 g.
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To convert grams to moles, we use the formula: moles = mass (g) / molar mass (g/mol) So, moles of KMnO4 = 0.0076 g / 158.034 g/mol = 4.81 x 10^-5 mol
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The volume of the solution is 50.0 mL, which is 0.0500 L.
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The concentration of the solution in mol/L is given by the formula: concentration = moles / volume (L) So, concentration of KMnO4 = 4.81 x 10^-5 mol / 0.0500 L = 9.62 x 10^-4 mol/L
Therefore, the concentration of the potassium permanganate solution is 9.62 x 10^-4 mol/L. This answer has three significant digits, which is appropriate given the precision of the original measurements.
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