Calculate the mass (in g) of potassium permanganate (KMnO4) required to make a 250 mL of a 0.826 M solution. Answer to 3 decimal places.MW(KMnO4) = 158.04 g.mol-1

A chemist prepares a solution of potassium permanganate KMnO4 by measuring out 7.6mg of potassium permanganate into a 50.mL volumetric flask and filling the flask to the mark with water.Calculate the concentration in /molL of the chemist's potassium permanganate solution. Be sure your answer has the correct number of significant digits.

Find out equivalent mass of KMnO4 in acidic medium of molar mass is M

Calculate the amount of KMnO4 (in grams) required to prepare a 0.01 M solution in 200 mL of waterYour answer

In order to complete the lab, a 500 mL solution of 0.25 M potassium oxide was required. What mass of potassium oxide was used? Question 2 options: 6.89 g 25.2 g 0.125 g 47.1 g 11.8 g

You need to prepare 0.500 L of a solution of potassium sulfate.The required molar concentration (molarity) is 0.127 mol L-1 potassium sulfate.Calculate the mass of potassium sulfate in grams required for this solution.Enter your answer with three significant figures, do not include units.