What volume of 0.0334 M KIO3 solution A is needed to make 25 mL of 0.005 M solution A?
Question
What volume of 0.0334 M KIO3 solution A is needed to make 25 mL of 0.005 M solution A?
Solution
To solve this problem, you can use the formula for dilution: M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
Here's the step-by-step solution:
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Identify the given values: M1 (initial molarity) = 0.0334 M M2 (final molarity) = 0.005 M V2 (final volume) = 25 mL
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Substitute the given values into the formula: (0.0334 M) * V1 = (0.005 M) * (25 mL)
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Solve for V1: V1 = (0.005 M * 25 mL) / 0.0334 M V1 = 3.74 mL
So, you will need approximately 3.74 mL of the 0.0334 M KIO3 solution to make 25 mL of a 0.005 M solution.
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