The function ๐(๐ฅ)=๐ฅ2โ9๐ฅโ3 can be made continuous at ๐ฅ=3 by defining ๐(3) to be:
Question
The function ๐(๐ฅ)=๐ฅ2โ9๐ฅโ3 can be made continuous at ๐ฅ=3 by defining ๐(3) to be:
Solution
The function f(x) = x^2 - 9x - 3 is a polynomial function, and polynomial functions are continuous everywhere in their domain. Therefore, the function is already continuous at x = 3. The value of the function at x = 3 is f(3) = 3^2 - 9*3 - 3 = 9 - 27 - 3 = -21. So, f(3) is already defined and equals -21.
Similar Questions
The function ๐(๐ฅ)=๐ฅ2โ9๐ฅโ3 can be made continuous at ๐ฅ=3 by defining ๐(3) to be:Group of answer choices96-6-9
Find the value of the constant ๐ that will make this piecewise function continuous everywhere.๐(๐ฅ)=โงโฉโจโชโช๐ฅ+1๐1โ๐ฅ๐ฅ<0๐ฅ=0๐ฅ>0
Which function has a discontinuity at x=3?Responsesf(x)={3x+1ย forย x<3x2+1ย forย xโฅ3๐(๐ฅ)={3๐ฅ+1ย ๐๐๐ย ๐ฅ<3๐ฅ2+1ย ๐๐๐ย ๐ฅโฅ3f(x)={3x+1ย forย x<3x2+1ย forย xโฅ3๐(๐ฅ)={3๐ฅ+1ย ๐๐๐ย ๐ฅ<3๐ฅ2+1ย ๐๐๐ย ๐ฅโฅ3f(x)=|xโ3|+2๐(๐ฅ)=|๐ฅโ3|+2f of x is equal to start absolute value x minus 3 end absolute value plus 2f(x)=xโ3x2๐(๐ฅ)=๐ฅโ3๐ฅ2f of x is equal to the fraction with numerator x minus 3 and denominator x squaredf(x)=x+2x2โ9
Determine the continuity of the function ๐๐ฅ=๐ฅ3-๐ฅ
ist the value(s) of ๐ฅ at which ๐ is discontinuous.
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