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The function ๐‘“(๐‘ฅ)=๐‘ฅ2โˆ’9๐‘ฅโˆ’3 can be made continuous at ๐‘ฅ=3 by defining ๐‘“(3) to be:Group of answer choices96-6-9

Question

The function ๐‘“(๐‘ฅ)=๐‘ฅ2โˆ’9๐‘ฅโˆ’3 can be made continuous at ๐‘ฅ=3 by defining ๐‘“(3) to be:Group of answer choices96-6-9

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Solution

The function f(x) = x^2 - 9x - 3 is a polynomial function, and polynomial functions are continuous everywhere in their domain. Therefore, the function is already continuous at x = 3.

However, if you want to find the value of the function at x = 3, you can substitute x = 3 into the function:

f(3) = (3)^2 - 9*(3) - 3 = 9 - 27 - 3 = -21

So, f(3) = -21.

The options you provided (96, -6, -9) do not include this result. There might be a mistake in the question or the provided options.

This problem has been solved

Similar Questions

The function ๐‘“(๐‘ฅ)=๐‘ฅ2โˆ’9๐‘ฅโˆ’3 can be made continuous at ๐‘ฅ=3 by defining ๐‘“(3) to be:

Which function has a discontinuity at x=3?Responsesf(x)={3x+1ย forย x<3x2+1ย forย xโ‰ฅ3๐‘“(๐‘ฅ)={3๐‘ฅ+1ย ๐‘“๐‘œ๐‘Ÿย ๐‘ฅ<3๐‘ฅ2+1ย ๐‘“๐‘œ๐‘Ÿย ๐‘ฅโ‰ฅ3f(x)={3x+1ย forย x<3x2+1ย forย xโ‰ฅ3๐‘“(๐‘ฅ)={3๐‘ฅ+1ย ๐‘“๐‘œ๐‘Ÿย ๐‘ฅ<3๐‘ฅ2+1ย ๐‘“๐‘œ๐‘Ÿย ๐‘ฅโ‰ฅ3f(x)=|xโˆ’3|+2๐‘“(๐‘ฅ)=|๐‘ฅโˆ’3|+2f of x is equal to start absolute value x minus 3 end absolute value plus 2f(x)=xโˆ’3x2๐‘“(๐‘ฅ)=๐‘ฅโˆ’3๐‘ฅ2f of x is equal to the fraction with numerator x minus 3 and denominator x squaredf(x)=x+2x2โˆ’9

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List the value(s) of ๐‘ฅ at which ๐‘“ is discontinuous.Group of answer choicesโˆ’5,โˆ’2,1,3,4,5-7,1,3,4,5โˆ’4,5โˆ’5,โˆ’2,1

For the function ๐‘“(๐‘ฅ)=5๐‘ฅโˆ’3 find ๐‘“(โˆ’3).Group of answer choicesโˆ’121412โˆ’18

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