Let's denote the marks of the two students as x and y. According to the problem, we know that:

1. One student has 9 marks more than the other. We can express this as: y = x + 9.

2. The marks of the student who got more (y) is 56% of the sum of their marks. We can express this as: y = 0.56 * (x + y).

Now we can solve these two equations to find the values of x and y.

First, substitute y from the first equation into the second equation:

x + 9 = 0.56 * (x + x + 9)

Simplify the equation:

x + 9 = 0.56 * (2x + 9)

Expand the right side:

x + 9 = 1.12x + 5.04

Subtract x from both sides:

9 - 5.04 = 1.12x - x

3.96 = 0.12x

Divide both sides by 0.12:

x = 3.96 / 0.12 = 33

Substitute x = 33 into the first equation to find y:

y = x + 9 = 33 + 9 = 42

So, the two students got 33 and 42 marks respectively.

Question

Let's denote the marks of the two students as x and y. According to the problem, we know that:

1. One student has 9 marks more than the other. We can express this as: y = x + 9.

2. The marks of the student who got more (y) is 56% of the sum of their marks. We can express this as: y = 0.56 * (x + y).

Now we can solve these two equations to find the values of x and y.

First, substitute y from the first equation into the second equation:

x + 9 = 0.56 * (x + x + 9)

Simplify the equation:

x + 9 = 0.56 * (2x + 9)

Expand the right side:

x + 9 = 1.12x + 5.04

Subtract x from both sides:

9 - 5.04 = 1.12x - x

3.96 = 0.12x

Divide both sides by 0.12:

x = 3.96 / 0.12 = 33

Substitute x = 33 into the first equation to find y:

y = x + 9 = 33 + 9 = 42

So, the two students got 33 and 42 marks respectively.

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