A gets 40% marks in an exam and he received 40 less marks than passing marks. B gets 70% marks in same exam and received 20 more marks than passing marks. If C gets 65% marks in the same exam, then find the difference between marks received by A and C in the exam.

Let's solve the problem step by step:

1. Let's assume the passing marks for the exam are represented by P.

2. According to the given information, A gets 40% marks in the exam, which means A scored 40/100 * P = 0.4P marks.

3. It is also mentioned that A received 40 less marks than the passing marks. So, we can write the equation as 0.4P = P - 40.

4. Solving the equation, we find P = 100.

5. Now, we know the passing marks are 100.

6. B gets 70% marks in the exam, which means B scored 70/100 * 100 = 0.7 * 100 = 70 marks.

7. It is mentioned that B received 20 more marks than the passing marks. So, B's total marks are 100 + 20 = 120.

8. C gets 65% marks in the exam, which means C scored 65/100 * 100 = 0.65 * 100 = 65 marks.

9. To find the difference between the marks received by A and C, we subtract C's marks from A's marks: 0.4P - 65 = 0.4 * 100 - 65 = 40 - 65 = -25.

10. Therefore, the difference between the marks received by A and C in the exam is -25 marks.

Let's solve the problem step by step:

1. Let's assume the passing marks for the exam are represented by P.

2. According to the given information, A gets 40% marks in the exam, which means A scored 40/100 * P = 0.4P marks.

3. It is also mentioned that A received 40 less marks than the passing marks. So, we can write the equation as 0.4P = P - 40.

4. Solving the equation, we find P = 100.

5. Now, we know the passing marks are 100.

6. B gets 70% marks in the exam, which means B scored 70/100 * 100 = 0.7 * 100 = 70 marks.

7. It is mentioned that B received 20 more marks than the passing marks. So, B's total marks are 100 + 20 = 120.

8. C gets 65% marks in the exam, which means C scored 65/100 * 100 = 0.65 * 100 = 65 marks.

9. To find the difference between the marks received by A and C, we subtract C's marks from A's marks: 0.4P - 65 = 0.4 * 100 - 65 = 40 - 65 = -25.

10. Therefore, the difference between the marks received by A and C in the exam is -25 marks.

Let's solve the problem step by step:

1. Let's assume the passing marks for the exam are represented by P.

2. According to the given information, A gets 40% marks in the exam, which means A scored 40/100 * P = 0.4P marks.

3. It is also mentioned that A received 40 less marks than the passing marks. So, we can write the equation as 0.4P = P - 40.

4. Solving the equation, we find P = 100.

5. Now, we know the passing marks are 100.

6. B gets 70% marks in the exam, which means B scored 70/100 * 100 = 0.7 * 100 = 70 marks.

7. It is mentioned that B received 20 more marks than the passing marks. So, B's total marks are 100 + 20 = 120.

8. C gets 65% marks in the exam, which means C scored 65/100 * 100 = 0.65 * 100 = 65 marks.

9. To find the difference between the marks received by A and C, we subtract C's marks from A's marks: 0.4P - 65 = 0.4 * 100 - 65 = 40 - 65 = -25.

10. Therefore, the difference between the marks received by A and C in the exam is -25 marks.