Let's denote the marks of the first student as x and the marks of the second student as x + 9 (since one student scored 9 marks more than the other).

According to the problem, the marks of the second student are 56% of the total marks of both students. This can be written as:

(x + 9) = 0.56 * (x + x + 9)

Solving this equation will give us the marks of both students.

First, simplify the right side of the equation:

(x + 9) = 0.56 * (2x + 9)

Then, distribute 0.56 to both terms inside the parentheses:

(x + 9) = 1.12x + 5.04

Next, subtract 1.12x from both sides of the equation:

-0.12x + 9 = 5.04

Then, subtract 9 from both sides:

-0.12x = -3.96

Finally, divide both sides by -0.12 to solve for x:

x = 33

So, the first student scored 33 marks and the second student scored 33 + 9 = 42 marks. Therefore, the answer is 33 and 42.

Question

Let's denote the marks of the first student as x and the marks of the second student as x + 9 (since one student scored 9 marks more than the other).

According to the problem, the marks of the second student are 56% of the total marks of both students. This can be written as:

(x + 9) = 0.56 * (x + x + 9)

Solving this equation will give us the marks of both students.

First, simplify the right side of the equation:

(x + 9) = 0.56 * (2x + 9)

Then, distribute 0.56 to both terms inside the parentheses:

(x + 9) = 1.12x + 5.04

Next, subtract 1.12x from both sides of the equation:

-0.12x + 9 = 5.04

Then, subtract 9 from both sides:

-0.12x = -3.96

Finally, divide both sides by -0.12 to solve for x:

x = 33

So, the first student scored 33 marks and the second student scored 33 + 9 = 42 marks. Therefore, the answer is 33 and 42.

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